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Sep 27th, 2016
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  1. for_each(a, a+N, [](auto &x){swap(x,*(&x+N)); } );
  2.  
  3. double number = 0;
  4. for(int I = 0; I < n[половина длины массива]; I++)
  5. {
  6. number = mas[I];
  7. mas[I] = mas[I+n];
  8. mas[I+n] = number;
  9. }
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