Another coding question ^^

Hmm, yet another question for the coders, please ? ^_^

My "previously current" renaming shell relied on this line, which was annoyingly making committing mistakes SUPER easy, for instance :
mv $file ${file%.zip_\(English\).zip}_.zip
Using that script led me to making minor mistakes, there were occasional strings combos that I hadn't imagined breaking everything... You can picture the loss of time - I blame nobody but me, of course.
And then I found this PERFECTLY SIMPLE replacement script, with the replacement arguments in the command line :
(source : http://superuser.com/questions/508731/find-and-replace-string-in-filenames )
It even allows single quotes, no more escaping or white spaces hell ! YAY.

#!/bin/bash
(( $# != 2 )) && exit 1
for f in *.zip; do
  newf="${f//$1/$2}"
  if [[ $f != $newf ]]; then
    mv "$f" "$newf"
  fi
done

Running it :
./replacestr 'original text' 'new text'


Now, I wanted to combine it with my idea, a .txt file containing the list of the only files that I want to rename.
After all, it worked with the previous script :

#!/bin/bash
for file in *.zip
do
mv $file ${file%_\(English\).zip}__\(English\).zip
done

Running it :
cat fixzips-list.txt | xargs ./rename

I wanted to do an adaptation of the same with the new renaming script :

cat fixzips-list.txt | xargs ./replacestr '(www.hentai' '(www.TROLOLOL'
... except that, this time, it didn't work, the renaming wasn't done.

Please, do you see what kind of option I might have missed ?
I don't think a {} should be added here, but, I might be mistaken... Ah well, I don't know ^^
Thanks if you can help ! :)