double-break performance

static int find = 2500;
static int sideEffect = 0;

bool function1()
{
  sideEffect *= find;
  bool found = false;
  for (int bar =0; !found && bar < 100; ++bar)
    for(int foo = 0; !found && foo < 100; ++foo)
      if (foo * bar == find)
        found = true;
  return found;
}
bool function2()
{
  sideEffect *= find;
  for (int bar =0; bar < 100; ++bar)
    for(int foo = 0; foo < 100; ++foo)
      if (foo * bar == find)
        return 1;
  return 0;
}
bool function3()
{
  sideEffect *= find;
  bool result = false;
  for (int bar =0; bar < 100; ++bar)
    for(int foo = 0; foo < 100; ++foo)
      if ( (result=(foo * bar == find)) )
        goto end;
end:
  return result;
}
bool function4()
{
  try
  {
  sideEffect *= find;
  for (int bar =0; bar < 100; ++bar)
    for(int foo = 0; foo < 100; ++foo)
      if (foo * bar == find)
        throw true;
  }
  catch(bool b) { return b; }
  return 0;
}

void Test()
{
    scanf("%d", &find);
    u8 stackMem[1024];
    StackAlloc stack( stackMem, 1024 );
    Scope scope( stack, "main" );
    Timer& timer = *eiNew(scope, Timer)();

    int r = 0;
    double b, e;
    b = timer.Elapsed();
    for( int i=0; i!=10000; ++i )
        r += (int)function2();
    e = timer.Elapsed();
    double t1 = e-b;

    b = timer.Elapsed();
    //for( int j=0; j!=10000; ++j )
    for( int i=0; i!=100000; ++i )
        r += (int)function2();
    e = timer.Elapsed();
    t1 = e-b;
    b = timer.Elapsed();
    //for( int j=0; j!=10000; ++j )
    for( int i=0; i!=100000; ++i )
        r += (int)function1();
    e = timer.Elapsed();
    double t2 = e-b;
    b = timer.Elapsed();
    //for( int j=0; j!=10000; ++j )
    for( int i=0; i!=100000; ++i )
        r += (int)function3();
    e = timer.Elapsed();
    double t3 = e-b;
    b = timer.Elapsed();
    //for( int j=0; j!=10000; ++j )
    for( int i=0; i!=100000; ++i )
        r += (int)function4();
    e = timer.Elapsed();
    double t4 = e-b;

    printf( "%f, %f, %f, %f\n %d\n", t1, t2, t3, t4, r+sideEffect );
}