Exams - Logs Aggregator

/* You are given a sequence of access logs in format <IP> <user> <duration>. Write a program to aggregate
the logs data and print for each user the total duration of his sessions and a list of unique IP addresses
in format "<user>: <duration> [<IP1>, <IP2>, …]". Order the users alphabetically.
Order the IPs alphabetically. */

function aggregator(arr) {
    var countLogs = Number(args[0]);
    var aggregator = {};
    var i;
    for (i = 0; i < countLogs; i += 1) {
        var logLine = args[i + 1].split(/\s+/).filter(Boolean);
        var IPaddress = logLine[0].trim();
        var user = logLine[1].trim();
        var duration = Number(logLine[2]);

        if (!(aggregator.hasOwnProperty(user))) {
            aggregator[user] = { duration: 0, IP_addresses: [] };
        }

        aggregator[user].duration += duration;
        if (aggregator[user].IP_addresses.indexOf(IPaddress) < 0) {
            aggregator[user].IP_addresses.push(IPaddress);
        }
    }

    var sortedNames = Object.keys(aggregator).sort();
    for (i = 0; i < sortedNames.length; i += 1) {
        if (aggregator.hasOwnProperty(sortedNames[i])) {
            aggregator[sortedNames[i]].IP_addresses.sort();
            console.log("%s: %s [%s]", sortedNames[i], aggregator[sortedNames[i]].duration,
                aggregator[sortedNames[i]].IP_addresses.join(', '));
        }
    }
}

aggregator(['7',
    '192.168.0.11 peter 33',
    '10.10.17.33 alex 12',
    '10.10.17.35 peter 30',
    '10.10.17.34 peter 120',
    '10.10.17.34 peter 120',
    '212.50.118.81 alex 46',
    '212.50.118.81 alex 4'
]);