Problem No 8

//Given a positive integer n, n integers and another integer p, print all the integers among n integers which are greater than p.
//Input:
//Inputs are positive integer n, followed by n integers and the integer p. You can assume that the maximum value of n is 1000.
//Output:
//Outputs are all the integers among n integers which are greater than p; if no such integer exists output is the text “None”, without the inverted commas.


#include<iostream>
using namespace std;


int main(){
int n,p,a[1000],counter=0;
cin>>n;
for(int i=0;i<n;i++){
    cin>>a[i];


}
for(int i=0;i<n;i++){
    cout<<a[i]<<" ";
}
cout<<endl;
cin>>p;
for(int i=0;i<n;i++){

    if(a[i]>p)cout<<a[i]<< " ";
    counter=1;
}
if(counter=0)cout<<endl<<" None";

return 0;
}