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May 20th, 2016
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  1. for (int i = 0; i < 10000; ++i){
  2. wejscie1 >> x[i] >> y[i];
  3. if ((pow (x[i]-200, 2) + pow(y[i]-200, 2))==200*200 ){
  4. wyjscie1<< x[i] << " "<< y[i] << endl;
  5. }
  6. else if ((pow (x[i]-200, 2) + pow(y[i]-200, 2))<200*200){
  7. licznik1++;
  8. }
  9. }
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