Symmetric Numbers in Range

/* Write a program to generate and print all symmetric numbers in given range
 * [start…end] (0 ≤ start ≤ end ≤ 999).
 * A number is symmetric if its digits are symmetric toward its middle.
 * For example, the numbers 101, 33, 989 and 5 are symmetric,
 * but 102, 34 and 997 are not symmetric.*/

import java.util.Scanner;

public class _01_SymmetricNumbersInRange {

    public static void main(String[] args) {
        // TODO Auto-generated method stub
        Scanner scan = new Scanner(System.in);
        System.out.println("Enter two Integer numbers in the Range [0 .. 999], separated by a space:");
        int firstNum = scan.nextInt();
        int secondNum = scan.nextInt();

        if (firstNum >= 0 && firstNum < 1000 && secondNum >= 0 && secondNum < 1000) {
            int start = firstNum;
            int end = secondNum;
            if (firstNum > secondNum) {
                start = secondNum;
                end = firstNum;
            }

            System.out.println("All Symmetric numbers in given range are:");
            for (int i = start; i <= end; i++) {
                boolean numberIsSymmetric = checkTheNumberIsSymmetric(i);
                if (numberIsSymmetric) {
                    System.out.print(i + " ");
                }
            }
        } else {
            System.out.println("Error! - Input number is Out of Range!!!");
        }
    }

    private static boolean checkTheNumberIsSymmetric(int number) {
        if (number < 10) {
            return true;
        }

        int lastDigit = number % 10;
        int firstDigit = number / 100;
        if (number < 100) {
            firstDigit = number / 10;
        }

        return firstDigit == lastDigit;
    }

}