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Dec 18th, 2014
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  1. (defun fizzbuzz (n)
  2. (cond
  3. ((= (% n 15) 0) "FizzBuzz")
  4. ((= (% n 5) 0) "Buzz")
  5. ((= (% n 3) 0) "Fizz")
  6. (t n))) ; => fizzbuzz
  7.  
  8. (fizzbuzz 10) ; => "Buzz"
  9. (fizzbuzz 2) ; => 2
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