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- Exercice 1:
- Partie A:
- (E): y' - 2y = 4x^2 - 4x
- (E0): y' - 2y = 0
- Question 1:
- a(x) = 1
- b(x) = -2
- b(x) / a(x) = -2
- G(x) = -2x
- Solution de (E0): ke(2x)
- Question 2:
- f(x) = ax^2
- f'(x) = 2ax
- 2ax - 2(ax^2) = 4x^2 - 4x
- Ce qui fait que -2ax^2 = 4x^2
- Donc -2a = 4 et a = 4/-2
- a = -2
- Question 3:
- Solution: ke(2x) -2x^2
- Question 4:
- y(0) = 1
- <=> ke(2*0) - 2*0^2 = 1
- <=> k*1 - 0 = 1
- <=> k = 1
- e(2x) - 2x^2
- Partie B:
- g(x) = e(2x) - 2x^2
- Question 1:
- a) Développement limité à l'ordre 3 de e(2x)
- e(2x) = 1 + 2x + 2x^2 + 8x^3/6 + x^3E(x)
- e(2x) = 1 + 2x + 2x^2 + 4x^3/3 + x^3E(x) avec lim E(x) = 0 quand x /-> 0
- b) g(x) = 1 + 2x + 2x^2 + 4x^3/3 + x^3E(x) - 2x^2
- g(x) = 1 + 2x + 4x^3/3 + x^3E(x) avec lim E(x) = 0 quand x /-> 0
- Question 2:
- a) Equation de la tangente: y = 1 + 2x
- b) A faire
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