"""
A faster gaussian kernel density estimate (KDE).
Intended for computing the KDE on a regular grid (different use case than
scipy's original scipy.stats.kde.gaussian_kde()).
-Joe Kington
"""
__license__ = 'MIT License <http://www.opensource.org/licenses/mit-license.php>'
import numpy as np
import scipy as sp
import scipy.sparse
import scipy.signal
def fast_kde(x, y, gridsize=(200, 200), extents=None, nocorrelation=False, weights=None):
"""
Performs a gaussian kernel density estimate over a regular grid using a
convolution of the gaussian kernel with a 2D histogram of the data.
This function is typically several orders of magnitude faster than
scipy.stats.kde.gaussian_kde for large (>1e7) numbers of points and
produces an essentially identical result.
Input:
x: The x-coords of the input data points
y: The y-coords of the input data points
gridsize: (default: 200x200) A (nx,ny) tuple of the size of the output
grid
extents: (default: extent of input data) A (xmin, xmax, ymin, ymax)
tuple of the extents of output grid
nocorrelation: (default: False) If True, the correlation between the
x and y coords will be ignored when preforming the KDE.
weights: (default: None) An array of the same shape as x & y that
weighs each sample (x_i, y_i) by each value in weights (w_i).
Defaults to an array of ones the same size as x & y.
Output:
A gridded 2D kernel density estimate of the input points.
"""
#---- Setup --------------------------------------------------------------
x, y = np.asarray(x), np.asarray(y)
x, y = np.squeeze(x), np.squeeze(y)
if x.size != y.size:
raise ValueError('Input x & y arrays must be the same size!')
nx, ny = gridsize
n = x.size
if weights is None:
# Default: Weight all points equally
weights = np.ones(n)
else:
weights = np.squeeze(np.asarray(weights))
if weights.size != x.size:
raise ValueError('Input weights must be an array of the same size'
' as input x & y arrays!')
# Default extents are the extent of the data
if extents is None:
xmin, xmax = x.min(), x.max()
ymin, ymax = y.min(), y.max()
else:
xmin, xmax, ymin, ymax = map(float, extents)
dx = (xmax - xmin) / (nx - 1)
dy = (ymax - ymin) / (ny - 1)
#---- Preliminary Calculations -------------------------------------------
# First convert x & y over to pixel coordinates
# (Avoiding np.digitize due to excessive memory usage!)
xyi = np.vstack((x,y)).T
xyi -= [xmin, ymin]
xyi /= [dx, dy]
xyi = np.floor(xyi, xyi).T
# Next, make a 2D histogram of x & y
# Avoiding np.histogram2d due to excessive memory usage with many points
grid = sp.sparse.coo_matrix((weights, xyi), shape=(nx, ny)).toarray()
# Calculate the covariance matrix (in pixel coords)
cov = np.cov(xyi)
if nocorrelation:
cov[1,0] = 0
cov[0,1] = 0
# Scaling factor for bandwidth
scotts_factor = np.power(n, -1.0 / 6) # For 2D
#---- Make the gaussian kernel -------------------------------------------
# First, determine how big the kernel needs to be
std_devs = np.diag(np.sqrt(cov))
kern_nx, kern_ny = np.round(scotts_factor * 2 * np.pi * std_devs)
# Determine the bandwidth to use for the gaussian kernel
inv_cov = np.linalg.inv(cov * scotts_factor**2)
# x & y (pixel) coords of the kernel grid, with <x,y> = <0,0> in center
xx = np.arange(kern_nx, dtype=np.float) - kern_nx / 2.0
yy = np.arange(kern_ny, dtype=np.float) - kern_ny / 2.0
xx, yy = np.meshgrid(xx, yy)
# Then evaluate the gaussian function on the kernel grid
kernel = np.vstack((xx.flatten(), yy.flatten()))
kernel = np.dot(inv_cov, kernel) * kernel
kernel = np.sum(kernel, axis=0) / 2.0
kernel = np.exp(-kernel)
kernel = kernel.reshape((kern_ny, kern_nx))
#---- Produce the kernel density estimate --------------------------------
# Convolve the gaussian kernel with the 2D histogram, producing a gaussian
# kernel density estimate on a regular grid
grid = sp.signal.convolve2d(grid, kernel, mode='same', boundary='fill').T
# Normalization factor to divide result by so that units are in the same
# units as scipy.stats.kde.gaussian_kde's output.
norm_factor = 2 * np.pi * cov * scotts_factor**2
norm_factor = np.linalg.det(norm_factor)
norm_factor = n * dx * dy * np.sqrt(norm_factor)
# Normalize the result
grid /= norm_factor
return np.flipud(grid)