; Define main function (for linker)
global _main

; Define externs from C
extern _printf
extern _scanf
extern _exit

; Variables
section .data
	; 2 integers (filled with 4 bytes of zeroes - 32 bit empty int)
	; It's just a place in memory, just 32 bits in RAM
	int1: times 4 db 0
	int2: times 4 db 0
	; Texts, 10 is new line, 0 is null terminator (have to be on string's end)
	format_in: db '%d', 0
	format_out: db 'The result is: %d', 10, 0
	hello: db 'This program will multiply 2 numbers. Awesome, huh?', 10, 10, 0
	message: db 'Type a number: ', 0

; Code
section .text
_main:
	; We push hello msg on stack and call
	; printf(hello)
	push hello
	call _printf
	; Every argument pushed on stack is 4 bytes long
	; By adding 4 to stack pointer register we
	; are clearing the stack.
	add esp, 4

	; Integer no. 1,
	; printf(message)
	push message
	call _printf
	add esp, 4

	; scanf(format_in, int1)
	; arguments are reversed in asm
	push int1
	push format_in
	call _scanf
	add esp, 8 ; we pushed 2 arguments so 8 bytes

	; Integer no. 2,
	; printf(message)
	push message
	call _printf
	add esp, 4

	; scanf(format_in, int2)
	push int2
	push format_in
	call _scanf
	add esp, 8

	; Now we have read the input to int1 and int2
	; We move them to eax and ebx registers to perform multiplication.
	mov eax, [int1]
	mov ebx, [int2]

	; Mul multiplies eax with specified register
	; In eax we've got int1 so argument is ebx
	mul ebx
	; Result is 64-bit in edx (high) and eax (low) registers
	; We'll display only 32-bit of this number (eax register)

	; printf(format_out, (int1 * int2))
	push eax
	push format_out
	call _printf
	add esp, 8

	; Now we are exiting with code 0 (success)
	push 0
	call _exit
	add esp, 4
	ret