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FizzBuzz in Clojure with cond
ptrelford
Sep 25th, 2014
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Clojure
0.22 KB
| None
|
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(
map
(
fn
[
x
]
(
let
[
a
(
mod x
3
)
b
(
mod x
5
)
]
(
cond
(
and
(
=
a
0
)
(
=
b
0
)
)
(
str
"FizzBuzz"
)
(
=
a
0
)
(
str
"Fizz"
)
(
=
b
0
)
(
str
"Buzz"
)
:
else
(
str
x
)
)
)
)
(
range
1
100
)
)
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