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Nov 29th, 2014
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  1. def foldl1(iterable, func):
  2. return foldl(iterable[1:], func, iterable[0])
  3.  
  4. def foldl(iterable, func, acc):
  5. if len(iterable) == 0:
  6. return acc
  7. acc = func(iterable[0], acc)
  8. return foldl(iterable[1:], func ,acc)
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