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Dec 6th, 2016
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  1. f1 =
  2. f2 =
  3.  
  4. f1 (f2 (*) [1,2,3,4]) 5
  5.  
  6. let f1 = xs n -> map (f -> f n) xs; f2 = map in f1 (f2 (*) [1,2,3,4]) 5
  7. [5,10,15,20]
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