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Oct 10th, 2015
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  1. // P = 1*2 + 2*3*4 + 3*4*5*6 + ... + N*(N+1)*...*2N.
  2. private int huita(int N) {
  3. int result = 0;
  4. for (int i = 1; i <= N; i++){
  5. int part = 1;
  6. for (int j = i; j <= 2*i; j++) {
  7. part = part * j;
  8. }
  9. result = result + part;
  10. }
  11. return result;
  12. }
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