day of the week

"""
The program should take three arguments. The first will be a day, the second will be month, and the third will be year. Then, your program should compute the day of the week that date will fall on.
"""

import sys
import calendar

months = {
'january':1,
'february':2,
'march':3,
'april':4,
'may':5,
'june':6,
'july':7,
'august':8,
'september':9,
'october':10,
'november':11,
'december':12
}

weekday = {
0:'monday',
1:'tuesday',
2:'wednesday',
3:'thursday',
4:'friday',
5:'saturday',
6:'sunday',
}

def get_args():
    "Returns a dict of args"
    if len(sys.argv) <= 3:
        print "Not enough arguments!"
        print "I need:"
        print "\tThe day [1]"
        print "\tThe month [2]"
        print "\tThe year [3]"
        sys.exit(0)

    try:
        month = months[sys.argv[2].lower()]
    except:
        try:
            month = int(sys.argv[2])
        except:
            month = months[sys.argv[2]]

    return {'day': int(sys.argv[1]),'month':month,'year':int(sys.argv[3])}

def main(year,month,day):
    int_day = calendar.weekday(year,month,day)
    print weekday[int_day]

if __name__ == "__main__":
    date = get_args()
    year = date['year']
    month = date['month']
    day = date['day']
    main(year,month,day)