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Apr 20th, 2014
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  1. $sql = "SELECT COUNT(u.url) AS total, u.SiteTypeID, p.SiteType FROM sites AS u LEFT JOIN sitetypes AS p USING (SiteTypeID) WHERE SiteTypeID=3";
  2. $sq2 = mysqli_query($dbc, $sql);
  3.  
  4. $sq3 = "SELECT COUNT(u.url) AS total, u.SiteTypeID, p.SiteType FROM sites AS u LEFT JOIN sitetypes AS p USING (SiteTypeID) WHERE SiteTypeID=4";
  5. $sq4 = mysqli_query($dbc, $sq3);
  6.  
  7. $sq5 = "SELECT COUNT(u.url) as total, u.SiteTypeID, p.SiteType FROM sites AS u LEFT JOIN sitetypes AS p USING (SiteTypeID) WHERE SiteTypeID=5";
  8. $sq6 = mysqli_query($dbc, $sq5);
  9.  
  10.  
  11. echo $row['url'] $row['SiteType'];
  12. echo $row2['url'] $row2['SiteType'];
  13. echo $row3['url'] $row3['SiteType'];
  14.  
  15. <?php
  16.  
  17. $sql = "SELECT COUNT(u.url) AS total, u.SiteTypeID, p.SiteType
  18. FROM sites AS u
  19. LEFT JOIN sitetypes AS p USING (SiteTypeID)
  20. WHERE SiteTypeID IN (3, 4, 5)
  21. GROUP BY u.SiteTypeID, p.SiteType";
  22.  
  23. if ($sql2 = mysqli_query($dbc, $sql))
  24. {
  25. while ($row = mysqli_fetch_assoc($sql2))
  26. {
  27. echo $row["total"].." - ".$row["SiteTypeID"].." - ".$row["SiteType"]."<br >";
  28. }
  29. }
  30.  
  31. ?>
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