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- # C is invertible
- C <- matrix(c(1.9,1.4,1.4,1.4,1.9,1.4,1.4,1.4,2.0),3,3)
- # D is NOT invertible
- D <- matrix(c(.289,.109,0.0,.109,1.46,0.0,0,0,0),3,3)
- # E is invertible
- E <- matrix(c(4.0,3.0,2.0,3.0,5.0,1.0,2.0,1.0,6.0),3,3)
- # F is NOT invertible
- F <- matrix(c(0,0,0,0,3,1.5,0,1.5,3),3,3)
- A <- solve(C) %*% D
- B <- solve(E) %*% F
- I <- diag(3)
- # How to find solve(solve(A) + solve(B))?
- #
- # If A and B were equal, then the answer is
- # solve(2*C) %*% D
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