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Mar 1st, 2015
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C++ 0.36 KB | None | 0 0
  1. double SINUS ( double x , double eps ) {
  2.         double suma=x;
  3.         double ulamek=x;
  4.         int n=1;
  5.         while (ulamek>=eps ) {
  6.                 ulamek=ulamek*((x*x)/((2*n)*(2*n+1)));
  7.                 if (n % 2) suma-=ulamek;
  8.                 else suma+=ulamek;
  9.                 n++;
  10.         }
  11.         return suma;
  12. }
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