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Sep 18th, 2016
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  1. int jePalindrom(char *str)  //vraca 0 ako nije, 1 ako jeste
  2. {
  3.     int len = strlen(str), i;
  4.    
  5.     for(i = 0; i < len/2; i++)
  6.         if(str[i] != str[len-i-1])
  7.             return 0;
  8.            
  9.     return 1;
  10. }
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