Lexicographically comparison -the true one

function solve(args) {
    var arr = args[0].split("\n");

    var array1 = arr[0].trim().toLowerCase();
    var array2 = arr[1].trim().toLowerCase();

    var n1 = array1.length;
    var n2 = array2.length;

    if (n1 < n2) {
        console.log("<");
        return;
    }
    else if (n1 > n2) {
        console.log(">");
        return;
    }
    else {
        if (n1 === n2 && array1.localeCompare(array2)===0) {

            console.log("=");
            return;
        }
        else {
            for (var i = 0; i < n1; i++) {
                if (array1[i].localeCompare(array2[i])===-1) {
                    console.log("<");
                    return;
                }
                if (array1[i].localeCompare(array2[i])===1) {
                    console.log(">");
                    return;
                }
            }
        }
    }
}