function1();
function2();

Please look at the code written below:

function1() {
  $.ajax({
  url: myurl,
  type: 'GET',
  async:false,
  success: function(response) {
     function2();
  }
 });
}

function1() {
   ...
   $.ajax({
      url: '...',
      type: 'GET',
      success: function(data) {
         // this will be executed after the asynchronous method finishes
         function2();
      }
   });
}

function function1()
{
  //Ajax Call
  ..
  ..

  if (xmlhttp.readyState==4 && xmlhttp.status==200)
  {
    function2();
  }
}

function1() {
   $.ajax({
      url: myurl,
      type: 'GET',
      success: function(response) {
         function2();
      }
   });
}

function1(function() {

           function2();

        });

function function1() {
    $.ajax({
        url: "url",
        type: 'POST',
    }).success(function (html) {
        function2();
    });
}

function ajaxCall(){
   return $.get('your/api/call', {param:1});
}

function fun1(){
   console.log('Function 1 was called');
}

function fun2(){
   console.log('Function 2 was called');
}


ajaxCall().done(fun1).done(fun2);

$.when( $.get('your/api/call') )
   .then(function(){ alert(1); })
   .then(function(){ alert(2); });