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Dec 5th, 2016
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  1. byte[] linear = new byte[n * n];
  2.  
  3. int k = 0;
  4. for (int i = 0; i < n; i++)
  5. for (int j = 0; j < n; j++)
  6. linear[k++] = board[i][j];
  7.  
  8. return Arrays.hashCode(linear);
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