Вариант 7. Таск 2

#include <stdio.h>
#include <math.h>

int main() {
    double a, b, c, status = scanf("%lf%lf%lf", &a, &b, &c) == 3 && a < b && (b - a) / c == (int)((b - a) / c);

    for (double x = a; x <= b && status; x += c) {
        printf("%lf | ", x);
        if (x <= 5)
            printf("%lf", 4 * sin(4 * x + 1) + 0.5);
        else if (x <= 11)
            printf("%lf", pow(x, 2) / 11 + 0.5 * sin(3 * x));
        else
            printf("%lf", pow(x, 2) / (pow(x + 11, 2) + 2 * x + 1));

        printf("\n");
    }

    if (!status) printf("n/a");

    return 0;
}