3num

from itertools import permutations
import operator

def solve(n1, n2, n3, solution):
    operations = {
        operator.mul: "x",
        operator.truediv: "/",
        operator.sub: "-",
        operator.add: "+",
        operator.mod: "%",
        operator.pow: "^"
    }
    solutions = []
    for (a, b, c) in permutations([n1, n2, n3]):
        for op1 in operations:
            for op2 in operations:
                if op1(op2(a, b), c) == solution:
                    solutions.append("{} {} {} {} {} = {}".format(
                        a,
                        operations[op2],
                        b,
                        operations[op1],
                        c,
                        solution
                    ))
    return solutions

solve(10, 5, 7, 14)