How to Extract Link(s) details given on the page using selen

import java.util.List;
import java.util.concurrent.TimeUnit;

import org.openqa.selenium.By;
import org.openqa.selenium.WebDriver;
import org.openqa.selenium.WebElement;
import org.openqa.selenium.firefox.FirefoxDriver;


public class LinkExtractTest {


	public static void main(String[] args) {
		WebDriver myTestDriver = new FirefoxDriver();
		myTestDriver.get("http://tinyurl.com/6d7xz7k");

		myTestDriver.manage().window().maximize();
		myTestDriver.manage().timeouts().implicitlyWait(10,TimeUnit.SECONDS);
		// Get all links

		List<WebElement> AllPageLinks = myTestDriver.findElements(By.tagName("a"));

		System.out.println(AllPageLinks.size());

		for(int i =0 ; i<AllPageLinks.size();i++){
			if(AllPageLinks.get(i).getText()!="")
				System.out.println(AllPageLinks.get(i).getText());
		}

		System.out.println("Content_Left--------------------------------------------");
		AllPageLinks= myTestDriver.findElement(By.xpath("//div[@id='Content_Left']")).findElements(By.tagName("a"));
		System.out.println(AllPageLinks.size());

		for(int i =0 ; i<AllPageLinks.size();i++){
			if(AllPageLinks.get(i).getText()!="")
				System.out.println(AllPageLinks.get(i).getText());
		}

		myTestDriver.quit();


	}

}