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- ***
- prva
- #include<stdio.h>
- #include<stdlib.h>
- #define MAX 100
- int main()
- {
- int a[MAX], i, n, par=0, nep=0, razlika=0;
- printf("Vnesi go brojot na elementite vo nizata: \n");
- scanf("%d", &n);
- printf("Vnesi gi elementite: \n");
- for(i=1; i<=n; i++)
- {
- printf("a[%d]=", i);
- scanf("%d", &a[i]);
- }
- for(i=1; i<=n; i++)
- {
- if(a[i]%2==0)
- {
- par+=a[i];
- }
- else
- {
- nep+=a[i];
- }
- }
- printf("Zbirot na cifrite sto se naogaat na parni pozicii e: %d\n", par);
- printf("Zbirot na cifrite sto se naogaat na neparnite pozicii e: %d\n", nep);
- razlika=(par-nep);
- razlika= abs (razlika);
- printf("Razlikata e: %d", razlika);
- getchar();
- getchar();
- return 0;
- }
- ************
- vtora
- ************
- treta
- #include <stdio.h>
- int main()
- {
- int i,j,n;
- int mat[100][100];
- scanf("%d",&n);
- for (i=0; i<n; i++)
- {
- for (j=0; j<n; j++)
- {
- scanf("%d", &mat[i][j]);
- }
- }
- printf("nad glavna dijagonala\n");
- for (i=0; i<n-1; i++)
- {
- for (j=i+1; j<n; j++)
- printf("%d ", mat[i][j]);
- putchar('\n');
- }
- printf("pod glavna dijagonala\n");
- for (i=1; i<n; i++)
- {
- for (j=0; j<i; j++)
- printf("%2d ", mat[i][j]);
- putchar('\n');
- }
- printf("nad sporedna\n");
- for (i=0; i<n-1; i++)
- {
- for (j=0; j<n-1-i; j++)
- printf("%2d ", mat[i][j]);
- putchar('\n');
- }
- printf("pod sporedna\n");
- for (i=1; i<n; i++)
- {
- for (j=n-i; j<n; j++)
- printf("%2d ", mat[i][j]);
- putchar('\n');
- }
- return 0;
- }
- ***************
- cetvrta
- #include<stdio.h>
- #include<stdlib.h>
- #define max 100
- int main ()
- {
- int m[max][max];
- int i=0, j=0, n, temp;
- printf("Vnesi go n: ");
- scanf("%d", &n);
- printf("Vnesi gi elementite na matricata!\n");
- for(i=0; i<n; i++)
- for(j=0; j<n; j++)
- scanf("%d", &m[i][j]);
- system("cls");
- for(i=0; i<n-1; i++)
- for(j=0; j<n-1-i; j++)
- {
- if(m[i][j]>m[n-1-j][n-1-i])
- {
- temp=m[i][j];
- m[i][j]=m[n-1-j][n-1-i];
- m[n-1-j][n-1-i]=temp;
- }
- }
- printf("Transformiranata matricata e:\n");
- for(i=0; i<n; i++)
- {
- printf("\n");
- for(j=0; j<n; j++)
- {printf("%3d", m[i][j]);}
- }
- printf("\n\n");
- return 0;
- }
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