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Reverse of 8-bit bnmber

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Jun 22nd, 2014
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C# 0.56 KB | None | 0 0
  1. using System;
  2. class ReverseNumber
  3. {
  4.     static void Main()
  5.     {
  6.         ushort number = ushort.Parse(Console.ReadLine());
  7.         Console.WriteLine(Convert.ToString(number, 2).PadLeft(8, '0'));
  8.         ushort result = Reverse(number);
  9.         Console.WriteLine(result);
  10.         Console.WriteLine(Convert.ToString(result, 2).PadLeft(8, '0'));
  11.     }
  12.  
  13.     static ushort Reverse(ushort x)
  14.     {
  15.         ushort y = 0;
  16.         for (int i = 0; i < 8; ++i)
  17.         {
  18.             y <<= 1;
  19.             y |= (ushort)(x & 1);
  20.             x >>= 1;
  21.         }
  22.         return y;
  23.     }
  24. }
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