An array was declared and set to 6 elements = {5, 3, 4, 17, 22, 19}

A pointer to an int was initialized to minimart function call

The addresses of array[0] & array[2] were passed as references to the function

Within the function, the contents of the addresses were compared by use of pointers

if contents of a were less than the contents of b (5 < 4)
then return a
Otherwise, return b
Thus b was returned
This function gives the starting address of ptr, which is at pos[2] of the array

ptr[1] = 9
would change the contents from pos[3] to 9
{5, 3, 4, 9, 22, 19}

ptr += 2
ptr increments up from pos[2] to pos[4]

*ptr = -1
contents of pos[4] will be changed to -1
{5, 3, 4, 9, -1, 19}

*(array+1) = 79;
Since the array pointer automatically starts from 0,
seperate from the ptr pointer,
pos[1] of the array would be changed to 79
{5, 79, 4, 9, -1, 19}

For the following function, we are substracting
the pos of elements for both array and ptr
The difference from &array[5] - ptr would print 1
because a substraction of pos[5] - pos[4] would occur (6 - 5 = 1)
note: elements of arrays have a start of 0, not 1.

First swap function receives addresses for both array[0] and array[1]
They are passed as arguments into pointer a and b
The swapping of addresses occurs between pointers a and b
AND NOT to the actual array itself. Also as soon as the function terminates;
a and b will not not exist anymore in the memory
Thus, the array will remain the same {5, 79, 4, 9, -1, 19}

Second swap function receives addresses for both array[0]and array[2]
This function directly changes the contents of both elements of the array
Temp varible will hold the value of 5
Contents of pos[0] will be changed to 4
Contents of pos[2] will be changed to 5
The updated array will be {4, 79, 5, 9, -1, 19}

The for loop will print the elements in order
So compiler would display 4  79  5  9  -1  19
End of program