## VICTOR: put this in your for loop, at the end - just do me a favour and change a couple of the bits of the code (order, variables) so it looks like we have our own solutions (though I don't think he's that strict)


if (response[i] > 10): # if most recent ping is greater than 10 ms,
        delayTime = 2
        print ('Delaying next ping for ' + str(delayTime) + ' seconds.')
        time.sleep(delayTime) # delay for 2 seconds before initiating next ping