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Jun 25th, 2019
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  1. for s in range(x) #gives s values from 0 to sqrt(n)
  2.  
  3. for d in range(0,e,f) #gives d values from 0 to n / sqrt(n)
  4.  
  5. for si in range(s,e,f) #gives si values from 0 to n / sqrt(n), because the lowest value s has is 0.
  6.  
  7. for li in range(d,d+f) #gives li values from 0 to sqrt(n)
  8.  
  9. sqrt(n) * n * / sqrt(n) * n / sqrt(n) * sqrt(n) = n2
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