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a guest Mar 25th, 2019 62 Never
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  1. Question 1
  2.  
  3. The purpose of this experiment to determine the concentration of NaOH
  4.  
  5. Question 2
  6.  
  7. Molar mass of KHP = 204.22 gm/mol
  8.  
  9. Moles of KHP from 2.345 gm = 2.345 g / 204.22 gm/mol = 0.01148 Moles
  10.  
  11. Question 3
  12.  
  13. Balanced equation:
  14. NaOH(aq) + KHC8H4O4(aq) ====> KNaC8H4O4(aq) + H2O(l)
  15. Reaction type: double replacement
  16.  
  17. According to the above equation one mole of KHP will neutalize one mole of NaOH. Hence
  18.  
  19. Moles of NaOH needed = 0.01148 Moles
  20.  
  21. Question 4
  22.  
  23. Volume of NaOH used in the titration = 18.78 - 0.5 = 18.28 ml
  24.  
  25. Question 5
  26.  
  27. Concentration of NaOH = 0.01148 x 1000 / 18.28 = 0.6281 M
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