###ITERATION 1###
   Cb    Xb    x1    x2    x3    x4    x5    bt
    0    x3    -2    -1     1     0     0    -3
    0    x4     1    -1     0     1     0     1
    0    x5     1    -2     0     0     1    -1

Delta is: 6     4     0     0     0
Getting x3 out of basis
Gamma is: 3     4    -1    -1    -1
Inserting x1 into basis
###ITERATION 2###
   Cb    Xb    x1    x2    x3    x4    x5    bt
    6    x1     1   1/2  -1/2     0     0   3/2
    0    x4     0  -3/2   1/2     1     0  -1/2
    0    x5     0  -5/2   1/2     0     1  -5/2

Delta is: 0     1     3     0     0
Getting x5 out of basis
Gamma is: -1   2/5    -1    -1    -1
Inserting x2 into basis
###ITERATION 3###
   Cb    Xb    x1    x2    x3    x4    x5    bt
    6    x1     1     0  -2/5     0   1/5     1
    0    x4     0     0   1/5     1  -3/5     1
    4    x2     0     1  -1/5     0  -2/5     1

Delta is: 0     0  16/5     0   2/5
All delta are positive and so are betta, plan is optimal!
Oh noesf