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Feb 25th, 2018
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C 0.20 KB | None | 0 0
  1. for (i = 0; i < m; i++)
  2.     {
  3.         for (j = 0; j < k; j++)
  4.         {
  5.             tabC[i][j] = 0;
  6.             for (s = 0; s < n; s++)
  7.             {
  8.                 tabC[i][j] =tabC[i][j] + tabA[i][s] * tabB[s][j];
  9.             }
  10.         }
  11.         putchar('\n');
  12.     }
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