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Mar 19th, 2019
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  1. SELECT a.*
  2. FROM turtle_derby AS a
  3. INNER JOIN (SELECT turtle_id, DATE(`date`) AS day_date, MAX(`date`) AS maxdate
  4. FROM turtle_derby
  5. GROUP BY turtle_id, day_date) AS groupedtt
  6. ON a.turtle_id = groupedtt.turtle_id
  7. AND a.turtle_id = '175846'
  8. AND a.`date` = groupedtt.maxdate
  9. AND a.`date` > '2018-07-26'
  10. ORDER BY `a`.`date`
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