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Java ciklai vidrurkio skaiciavimas ir min/max skaiciu paiesk

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Apr 23rd, 2019
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  1. import java.util.Scanner;
  2.  
  3. public class Main {
  4.  
  5.     public static void main(String args[]) {
  6.         int[] a = {44, 33, 4, 100, 20, 10};
  7.         int max = a[0];
  8.         int min = a[0];
  9.        
  10.         int maxIndex = 0;
  11.  
  12.         for (int i = 1; i < a.length; i++) {
  13.             if (a[i] > max) {
  14.                 max = a[i];
  15.                 maxIndex = i;
  16.             }else if (a[i] < min) {
  17.                 min = a[i];
  18.             }
  19.         }
  20.  
  21.         System.out.println("Didziausias massive elementas:" + max);
  22.         System.out.println("Maziausias massive elementas:" + min);
  23.  
  24.  
  25.         int[] b = {5, 6, 10, 15, 8, 4};
  26.         int[] c = {8, 5, 3};
  27.  
  28.         int sumaB = 0;
  29.         int sumaC = 0;
  30.         double averageB;
  31.         double averageC;
  32.         double changer;
  33.         for (int i = 0; i < b.length; i++) {
  34.             sumaB += b[i];
  35.         }
  36.         for (int i = 0; i < c.length; i++) {
  37.             sumaC += c[i];
  38.         }
  39.         averageB = (double)sumaB / (double)b.length;
  40.         averageC = (double)sumaC / (double)c.length;
  41.         changer = averageB - averageC;
  42.  
  43.         System.out.println("massive B average:" + averageB);
  44.         System.out.println("massive C average:" + averageC);
  45.         System.out.println("massive changer:" + changer);
  46.     }
  47. }
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