sglazhivanie_posledovatelnosti

#include <iostream>

int main()
{
    using namespace std;

    int N = 6, i, k;
    int a[N];
    for(i = 0; i < N; i++)
        cin >> a[i];

    //начало своей части
    int j[N];
    for (i = 0; i < N; i++)
       j[i] = a[i];
    k = (a[0] + a[1]) / 2;
    cout << k << " ";
    for (i = 1; i < N - 1; i++)
       j[i] = (a[i - 1] + a[i] + a[i + 1]) / 3;
    for(i = 1; i < N - 1; i++)
        cout << j[i] << " ";
    a[N - 1] = (a[N - 2] + a[N - 1]) / 2;
    cout << a[N - 1];
    return 0;
}

//0   1   2   3   4   5
//1   9   2   10  3   11