#calculation of e, twice as fast as naive (1 + 1/n)n method.
from math import *
from decimal import *
d = Decimal

def sstr(var, cut=16)
  return d()


i = d(2)
while i < 600_000:
  standard = (e/((1+d(1/i))**i))
  improved = (e/(1/((1/((((1+d(1/(i-1)))**i) - ((1+d(1/(i-0)))**i))))/d(i-(1/i)))))
  print(f"i: {i}, standard: {sstr(standard)}, result: {sstr(improved)},  percent improved: {sstr((improved/standard)*100)}%")
  i = i + 1