#include <iostream>
#include <cmath>
using namespace std;
int main()
{
	float n;
	float x, p = 1, b;
	double k;
	cout << "x="; cin >> x;
	cout << "k="; cin >> k;
	for (n = 2; n <= k; n++)
		p = p*(1 + ((pow(-1, n)*pow(x, 2 * n - 1 / (pow(n, 3) - 1))
		cout << "p=" << p << endl;
	system("pause");
	return 0;
}