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- \chapter{Polynomial functions}
- \minitoc
- \section{Polynomial functions}
- \listspecialproblems
- %===================================
- % Author: Hughes
- % Date: May 2011
- %===================================
- \begin{pccdefinition}[Polynomial functions]
- Polynomial functions have the form
- \[
- p(x)=a_nx^n+a_{n+1}x^{n+1}+\ldots+a_1x+a_0
- \]
- where $a_n$, $a_{n+1}$, $a_{n+2}$, \ldots, $a_0$ are real numbers.
- \begin{itemize}
- \item We call $n$ the degree of the polynomial;
- \item $a_n$, $a_{n+1}$, $a_{n+2}$, \ldots, $a_0$ are called the coefficients;
- \item We typically write polynomial functions in descending powers of $x$.
- \end{itemize}
- In particular, we call $a_n$ the {\em leading} coefficient.
- \end{pccdefinition}
- %===================================
- % Author: Hughes
- % Date: May 2011
- %===================================
- \begin{figure}[!h]
- \centering
- \setlength{\figurewidth}{\textwidth/6}
- \setwindow{-10}{-10}{10}{10}{\figurewidth}
- \begin{subfigure}{\figurewidth}
- \begin{pspicture}(\xmin,\ymin)(\xmax,\ymax)
- \pccpsframe(\xmin,\ymin)(\xmax,\ymax)
- \psaxes[dx=10,Dx=10,dy=100,Dy=100]{<->}(0,0)(\xmin,\ymin)(\xmax,\ymax)[$x$,-90][$y$,180]
- \pccpsplot{-10}{8}{(x+2)}
- \end{pspicture}
- \caption{$a_1>0$}
- \end{subfigure}
- \hfill
- \begin{subfigure}{\figurewidth}
- \begin{pspicture}(\xmin,\ymin)(\xmax,\ymax)
- \pccpsframe(\xmin,\ymin)(\xmax,\ymax)
- \psaxes[dx=10,Dx=10,dy=100,Dy=100]{<->}(0,0)(\xmin,\ymin)(\xmax,\ymax)[$x$,-90][$y$,180]
- \pccpsplot{-4}{4}{(x^2-6)}
- \end{pspicture}
- \caption{$a_2>0$}
- \end{subfigure}
- \hfill
- \begin{subfigure}{\figurewidth}
- \begin{pspicture}(\xmin,\ymin)(\xmax,\ymax)
- \pccpsframe(\xmin,\ymin)(\xmax,\ymax)
- \psaxes[dx=10,Dx=10,dy=100,Dy=100]{<->}(0,0)(\xmin,\ymin)(\xmax,\ymax)[$x$,-90][$y$,180]
- \pccpsplot{-7.5}{7.5}{0.05*(x+6)*x*(x-6)}
- \end{pspicture}
- \caption{$a_3>0$}
- \end{subfigure}
- \hfill
- \begin{subfigure}{\figurewidth}
- \begin{pspicture}(\xmin,\ymin)(\xmax,\ymax)
- \pccpsframe(\xmin,\ymin)(\xmax,\ymax)
- \psaxes[dx=10,Dx=10,dy=100,Dy=100]{<->}(0,0)(\xmin,\ymin)(\xmax,\ymax)[$x$,-90][$y$,180]
- \pccpsplot[plotpoints=1000]{-2.35}{5.35}{0.2*(x-5)*x*(x-3)*(x+2)}
- \end{pspicture}
- \caption{$a_4>0$}
- \end{subfigure}
- \hfill
- \begin{subfigure}{\figurewidth}
- \begin{pspicture}(\xmin,\ymin)(\xmax,\ymax)
- \pccpsframe(\xmin,\ymin)(\xmax,\ymax)
- \psaxes[dx=10,Dx=10,dy=100,Dy=100]{<->}(0,0)(\xmin,\ymin)(\xmax,\ymax)[$x$,-90][$y$,180]
- \pccpsplot[plotpoints=1000]{-5.5}{6.3}{0.01*(x+2)*x*(x-3)*(x+5)*(x-6)}
- \end{pspicture}
- \caption{$a_5>0$}
- \end{subfigure}
- \caption{Graphs to illustrate typical shapes of polynomials.}
- \end{figure}
- %===================================
- % Author: Hughes
- % Date: May 2011
- %===================================
- \begin{problem}[Polynomial or not?][special]
- Identify whether each of the following functions is a polynomial or not.
- If the function is a polynomial, state its degree.
- \begin{multicols}{3}
- \begin{subproblem}[special]
- $p(x)=2x+1$
- \begin{shortsolution}
- $p$ is a polynomial (you might also describe $p$ as linear). The degree of $p$ is 1.
- \end{shortsolution}
- \end{subproblem}
- \begin{subproblem}
- $p(x)=7x^2+4x$
- \begin{shortsolution}
- $p$ is a polynomial (you might also describe $p$ as quadratic). The degree of $p$ is 2.
- \end{shortsolution}
- \end{subproblem}
- \begin{subproblem}
- $p(x)=\sqrt{x}+2x+1$
- \begin{shortsolution}
- $p$ is not a polynomial; we require the powers of $x$ to be integer values.
- \end{shortsolution}
- \end{subproblem}
- \begin{subproblem}
- $p(x)=2^x-45$
- \begin{shortsolution}
- $p$ is not a polynomial; the $2^x$ term is exponential.
- \end{shortsolution}
- \end{subproblem}
- \begin{subproblem}
- $p(x)=6x^4-5x^3+9$
- \begin{shortsolution}
- $p$ is a polynomial- the degree of $p$ is $6$.
- \end{shortsolution}
- \end{subproblem}
- \begin{subproblem}[special]
- $p(x)=-5x^{17}+9x+2$
- \begin{shortsolution}
- $p$ is a polynomial- the degree of $p$ is 17.
- \end{shortsolution}
- \end{subproblem}
- \end{multicols}
- \end{problem}
- %===================================
- % Author: Hughes
- % Date: May 2011
- %===================================
- \begin{problem}[Polynomial graphs]
- Three polynomial functions are shown in \crefrange{poly:fig:functionp}{poly:fig:functionn}.
- The functions $p$, $m$, $n$ have the following formulas
- \begin{align*}
- p(x)&= (x-1)(x+2)(x-3)\\
- m(x)&= -(x-1)(x+2)(x-3)\\
- n(x)&= (x-1)(x+2)(x-3)(x+1)(x+4)
- \end{align*}
- Note that for our present purposes we are not concerned with the vertical scale of the graphs.
- \end{problem}
- \begin{subproblem}
- Identify both on the graph {\em and} algebraically, the zeros of the polynomial.
- \begin{shortsolution}
- \setlength{\figurewidth}{\solutionfigurewidth}
- \begin{figure}[!h]
- \begin{subfigure}{\figurewidth}
- \setwindow{-5}{-10}{5}{10}{\figurewidth}
- \begin{pspicture}(\xmin,\ymin)(\xmax,\ymax)
- \psaxes[dx=1,Dx=1,dy=0,Dy=10]{<->}(0,0)(\xmin,\ymin)(\xmax,\ymax)[$x$,-90][$y$,180]
- \pccpsplot{-2.5}{3.5}{(x-1)*(x+2)*(x-3)}
- \pccpsSolDot(-2,0)(1,0)(3,0)
- \end{pspicture}
- \caption{$y=p(x)$}
- \end{subfigure}
- \begin{subfigure}{\figurewidth}
- \setwindow{-5}{-10}{5}{10}{\figurewidth}
- \begin{pspicture}(\xmin,\ymin)(\xmax,\ymax)
- \psaxes[dx=1,Dx=1,dy=0,Dy=10]{<->}(0,0)(\xmin,\ymin)(\xmax,\ymax)[$x$,-90][$y$,180]
- \pccpsplot{-2.5}{3.5}{-1*(x-1)*(x+2)*(x-3)}
- \pccpsSolDot(-2,0)(1,0)(3,0)
- \end{pspicture}
- \caption{$y=m(x)$}
- \end{subfigure}
- \begin{subfigure}{\figurewidth}
- \setwindow{-5}{-90}{5}{70}{\figurewidth}
- \begin{pspicture}(\xmin,\ymin)(\xmax,\ymax)
- \psaxes[dx=1,Dx=1,dy=0,Dy=100]{<->}(0,0)(\xmin,\ymin)(\xmax,\ymax)[$x$,-90][$y$,180]
- \pccpsplot{-4.15}{3.15}{(x-1)*(x+2)*(x-3)*(x+1)*(x+4)}
- \pccpsSolDot(-4,0)(-2,0)(-1,0)(1,0)(3,0)
- \end{pspicture}
- \caption{$y=n(x)$}
- \end{subfigure}
- \end{figure}
- The zeros of $p$ are $x=-2,1,3$; the zeros of $m$ are $x=-2,1,3$; the zeros of $n$ are $x=-4,-2,-1$, and $3$.
- \end{shortsolution}
- \end{subproblem}
- \begin{subproblem}[special]
- Write down the degree, how many times the graph `turns around', and how many zeros it has
- \begin{shortsolution}
- The degree of $p$ is 3, and it turns around twice. The degree of $q$ is also 3, and it turns around twice. The degree
- of $n$ is $5$, and it turns around 4 times.
- \end{shortsolution}
- \end{subproblem}
- \setlength{\figurewidth}{0.25\textwidth}
- \begin{figure}[!h]
- \begin{subfigure}{\figurewidth}
- \setwindow{-5}{-10}{5}{10}{\figurewidth}
- \begin{pspicture}(\xmin,\ymin)(\xmax,\ymax)
- \psaxes[dx=1,Dx=1,dy=0,Dy=10]{<->}(0,0)(\xmin,\ymin)(\xmax,\ymax)[$x$,-90][$y$,180]
- \pccpsplot{-2.5}{3.5}{(x-1)*(x+2)*(x-3)}
- \end{pspicture}
- \caption{$y=p(x)$}
- \label{poly:fig:functionp}
- \end{subfigure}
- \hfill
- \begin{subfigure}{\figurewidth}
- \setwindow{-5}{-10}{5}{10}{\figurewidth}
- \begin{pspicture}(\xmin,\ymin)(\xmax,\ymax)
- \psaxes[dx=1,Dx=1,dy=0,Dy=10]{<->}(0,0)(\xmin,\ymin)(\xmax,\ymax)[$x$,-90][$y$,180]
- \pccpsplot{-2.5}{3.5}{-1*(x-1)*(x+2)*(x-3)}
- \end{pspicture}
- \caption{$y=m(x)$}
- \label{poly:fig:functionm}
- \end{subfigure}
- \hfill
- \begin{subfigure}{\figurewidth}
- \setwindow{-5}{-90}{5}{70}{\figurewidth}
- \begin{pspicture}(\xmin,\ymin)(\xmax,\ymax)
- \psaxes[dx=1,Dx=1,dy=0,Dy=100]{<->}(0,0)(\xmin,\ymin)(\xmax,\ymax)[$x$,-90][$y$,180]
- \pccpsplot{-4.15}{3.15}{(x-1)*(x+2)*(x-3)*(x+1)*(x+4)}
- \end{pspicture}
- \caption{$y=n(x)$}
- \label{poly:fig:functionn}
- \end{subfigure}
- \caption{}
- \end{figure}
- %===================================
- % Author: Hughes
- % Date: May 2011
- %===================================
- \begin{problem}[Horizontal intercepts][special]\label{poly:prob:matchpolys}%
- State the horizontal intercepts (as ordered pairs) of the following polynomials.
- \end{problem}
- \begin{subproblem}\label{poly:prob:degree5}
- $p(x)=(x-1)(x+2)(x-3)(x+1)(x+4)$
- \begin{shortsolution}
- $(-4,0)$, $(-2,0)$, $(-1,0)$, $(1,0)$, $(3,0)$
- \end{shortsolution}
- \end{subproblem}
- \begin{subproblem}
- $q(x)=-(x-1)(x+2)(x-3)$
- \begin{shortsolution}
- $(-2,0)$, $(1,0)$, $(3,0)$
- \end{shortsolution}
- \end{subproblem}
- \begin{subproblem}
- $r(x)=(x-1)(x+2)(x-3)$
- \begin{shortsolution}
- $(-2,0)$, $(1,0)$, $(3,0)$
- \end{shortsolution}
- \end{subproblem}
- \begin{subproblem}\label{poly:prob:degree2}
- $s(x)=(x-2)(x+2)$
- \begin{shortsolution}
- $(-2,0)$, $(2,0)$
- \end{shortsolution}
- \end{subproblem}
- \begin{pccdefinition}[Linear factors of a polynomial]
- If a polynomial $p$ can be written in factored form
- \[
- p(x)=(x-x_1)(x-x_2)\ldots(x-x_n)
- \]
- then we call each of the factors $(x-x_i)$ the linear factors of $p$.
- \end{pccdefinition}
- %===================================
- % Author: Hughes
- % Date: May 2011
- %===================================
- \begin{problem}[Multiple zeros]
- Consider the polynomial
- \[
- p(x) = (x+3)^2(x-1).
- \]
- \end{problem}
- \begin{marginfigure}
- \setlength{\figurewidth}{\marginparwidth}
- \setwindow{-5}{-20}{2}{10}{\figurewidth}
- \centering
- \begin{pspicture}(\xmin,\ymin)(\xmax,\ymax)
- \psaxes[dx=1,Dx=1,dy=0,Dy=100]{<->}(0,0)(\xmin,\ymin)(\xmax,\ymax)[$x$,-90][$y$,180]
- \pccpsplot{-4.75}{1.5}{(x-1)*(x+3)^2}
- \end{pspicture}
- \caption{$p(x)=(x+3)^2(x-1)$}
- \label{poly:fig:multiplezeros}
- \end{marginfigure}
- \begin{subproblem}
- How is this different to the polynomials we have seen so far?
- \begin{shortsolution}
- $p$ has a repeated linear factor.
- \end{shortsolution}
- \end{subproblem}
- \begin{subproblem}
- How many linear factors does $p$ have?
- \begin{shortsolution}
- $p$ has 3 linear factors.
- \end{shortsolution}
- \end{subproblem}
- \begin{subproblem}
- What is the degree of this polynomial?
- \begin{shortsolution}
- The degree of $p$ is $3$.
- \end{shortsolution}
- \end{subproblem}
- Note that this polynomial can be written as
- \begin{align*}
- p(x) &=(x+3)^2(x-1)\\
- &=(x+3)(x+3)(x-1).
- \end{align*}
- Does this change your answers?
- \begin{subproblem}
- The graph of this polynomial is shown in \cref{poly:fig:multiplezeros}. Notice in
- particular the behavior of $p$ at $(-3,0)$. Does $p$ cut the horizontal axis, or bounce off it?
- \begin{shortsolution}
- $p$ bounces off the horizontal axis at $(-3,0)$.
- \end{shortsolution}
- \end{subproblem}
- \begin{subproblem}
- Now consider the polynomial functions in \cref{poly:fig:moremultiple}.
- The formulas for $p$, $q$, and $r$ are as follows
- \begin{align*}
- p(x)&=(x-3)^2(x+4)^2\\
- q(x)&=x(x+2)^2(x-1)^2(x-3)\\
- r(x)&=x(x-3)^3(x+1)^2
- \end{align*}
- Find the degree of $p$, $q$, and $r$, and decide if the functions bounce or cut at
- each of their zeros.
- \begin{shortsolution}
- \begin{itemize}
- \item The degree of $p$ is 4. It bounces at both zeros, $x=3$ and $x=4$.
- \item The degree of $q$ is 6. It bounces at $x=-2$ and $x=1$, and cuts at $x=0,3$.
- \item The degree of $r$ is 6. It bounces at $x=-1$, and cuts at $x=0$. It also
- cuts at $x=3$, although is flattened immediately to the left and right of $x=3$.
- \end{itemize}
- \end{shortsolution}
- \end{subproblem}
- \setlength{\figurewidth}{0.25\textwidth}
- \begin{figure}[!h]
- \centering
- \begin{subfigure}{\figurewidth}
- \setwindow{-5}{-30}{5}{200}{\figurewidth}
- \begin{pspicture}(\xmin,\ymin)(\xmax,\ymax)
- \psaxes[dx=2,Dx=2,dy=0,Dy=200]{<->}(0,0)(\xmin,\ymin)(\xmax,\ymax)[$x$,-90][$y$,180]
- \pccpsplot{-5}{4.25}{(x-3)^2*(x+4)^2}
- \end{pspicture}
- \caption{$y=p(x)$}
- \end{subfigure}
- \hfill
- \begin{subfigure}{\figurewidth}
- \setwindow{-3}{-60}{4}{40}{\figurewidth}
- \begin{pspicture}(\xmin,\ymin)(\xmax,\ymax)
- \psaxes[dx=1,Dx=1,dy=0,Dy=200]{<->}(0,0)(\xmin,\ymin)(\xmax,\ymax)[$x$,-90][$y$,180]
- \pccpsplot{-2.45}{3.05}{x*(x+2)^2*(x-1)^2*(x-3)}
- \end{pspicture}
- \caption{$y=q(x)$}
- \end{subfigure}
- \hfill
- \begin{subfigure}{\figurewidth}
- \setwindow{-2}{-40}{4}{40}{\figurewidth}
- \begin{pspicture}(\xmin,\ymin)(\xmax,\ymax)
- \psaxes[dx=1,Dx=1,dy=0,Dy=200]{<->}(0,0)(\xmin,\ymin)(\xmax,\ymax)[$x$,-90][$y$,180]
- \pccpsplot{-1.45}{3.75}{x*(x-3)^3*(x+1)^2}
- \end{pspicture}
- \caption{$y=r(x)$}
- \end{subfigure}
- \caption{}
- \label{poly:fig:moremultiple}
- \end{figure}
- \begin{pccdefinition}[Multiple zeros]
- Let $p$ be a polynomial that has a repeated linear factor $(x-k)^n$. Then we say
- that $p$ has a multiple zero at $x=k$ and
- \begin{itemize}
- \item if the factor $(x-k)$ is repeated an even number of times, the graph of $y=p(x)$ does not
- cross the $x$ axis at $x=k$, but `bounces' off the $x$ axis at $x=k$.
- \item if the factor $(x-k)$ is repeated an odd number of times, the graph of $y=p(x)$ crosses the
- $x$ axis at $x=k$, but it looks `flattened' there
- \end{itemize}
- \end{pccdefinition}
- %===================================
- % Author: Hughes
- % Date: May 2011
- %===================================
- \begin{margintable}
- \centering
- \caption{$p$ and $q$}
- \begin{tabular}{rrr}
- \beforeheading
- \heading{$x$} & \heading{$p(x)$} & \heading{$q(x)$} \\ \afterheading
- $-4$ & $-56$ & $-16$ \\\normalline
- $-3$ & $-18$ & $-3$ \\ \normalline
- $-2$ & $0$ & $0$ \\ \normalline
- $-1$ & $4$ & $-1$ \\ \normalline
- $0$ & $0$ & $0$ \\ \normalline
- $1$ & $-6$ & $9$ \\ \normalline
- $2$ & $-8$ & $32$ \\ \normalline
- $3$ & $0$ & $75$ \\ \normalline
- $4$ & $24$ & $144$ \\\lastline
- \end{tabular}
- \label{poly:tab:findformula}
- \end{margintable}
- \begin{problem}[Find a formula from a table]
- \Cref{poly:tab:findformula} shows two polynomial functions, $p$ and $q$.
- \end{problem}
- \begin{subproblem}
- Assuming that all of the zeros of $p$ are shown, how many zeros does $p$ have?
- \begin{shortsolution}
- $p$ has 3 zeros.
- \end{shortsolution}
- \end{subproblem}
- \begin{subproblem}
- What is the degree of $p$?
- \begin{shortsolution}
- $p$ is degree 3.
- \end{shortsolution}
- \end{subproblem}
- \begin{subproblem}
- Write a formula for $p(x)$.
- \begin{shortsolution}
- $p(x)=x(x+2)(x-3)$
- \end{shortsolution}
- \end{subproblem}
- \begin{subproblem}
- Assuming that all of the zeros of $q$ are shown, how many zeros does $q$ have?
- \begin{shortsolution}
- $q$ has 2 zeros.
- \end{shortsolution}
- \end{subproblem}
- \begin{subproblem}
- Describe the difference in behavior of $p$ and $q$ at $x=-2$.
- \begin{shortsolution}
- $p$ changes sign at $x=-2$, and $q$ does not change sign at $x=-2$.
- \end{shortsolution}
- \end{subproblem}
- \begin{subproblem}[special]
- Given that $q$ is a degree 3 polynomial, write a formula for $q(x)$.
- \begin{shortsolution}
- $q(x)=x(x+2)^2$
- \end{shortsolution}
- \end{subproblem}
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