#include <iostream>
#include <cmath>
#include <conio.h>
using namespace std;

int main ()
{
    int N = 5;
    double a[N][N];
    int i, j, k;

    for (i = 0; i < N; ++i)
    {
        for (j = 0; j < N; ++j)
        {
            a[i][j] = cos(pow(i, 2.0) + N);
            cout << a [i][j] << " ";
            }
        cout << endl;
        }
    cout << "\n";

    k = 0;
    for (i = 0; i < N; ++i)
    {
        for (j = 0; j < N; ++j)
        {
            if (a[i][j] > 0)
            ++k;
            }
        }
    cout << "kolichestvo polozhitel'nih elementov ravno " << k;

    getch ();
    return 0;
    }