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Apr 21st, 2018
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  1. (let (binop? (lambda (expr) (if (pair? expr) ;; z racji chwilowego braku 'and' / 'andmap' uzywam condow
  2. (cond
  3. [(eq? '+ (car expr)) true]
  4. [(eq? '- (car expr)) true]
  5. [(eq? '* (car expr)) true]
  6. [(eq? '/ (car expr)) true]
  7. [true false])
  8. false)))
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