from itertools import chain

dictionary=open("Scrabble.txt").read().split('n')

import re,string

#after replacing the word with "_", we find words in the dictionary that match the pattern
def wordshape(word):
    new=[]
    for letter in string.ascii_lowercase:
        underscore=re.sub('_', letter, word)
        if underscore in dictionary:
            new.append(underscore)
    if new == []:
        pass
    else:
        return new