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Nov 19th, 2019
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  1. else
  2. {
  3. if (sens>0 && i+sens>=N)
  4. {
  5. sens = -1;
  6. }
  7. else if (sens<0 && i==0 && j==0)
  8. {
  9. break;
  10. }
  11. else
  12. {
  13. i+=sens;
  14. seq[k]=(sens==1) ? 'v' : '^';
  15. k++;
  16. }
  17.  
  18. }
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