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- %% Inlämningsuppgift Tribologi
- % Givna konstanter, samband och värden
- M0 = 6;
- n0 = 1800;
- k = 119;
- R = 0.025;
- alfaN = 20; % grader
- beta = 18; % grader
- sigmaTN = 2.9E8;
- nmin = 0.25*n0;
- n = nmin;
- M = M0*(1-n/n0);
- F = k*M;
- Fh = M/R;
- Fv = M*tand(alfaN)/(R*cosd(beta));
- Fa = M*tand(beta)/R;
- T = 80;
- etac = 0.2;
- %% Uppgift 3
- % Gissade värden på bredd
- bA = 0.01;
- bB = 0.01;
- % Krafter
- FBa = F - Fa
- FBv = (Fv*(0.03/2 + bA/2) - Fa*R)/(0.03 + bA/2 + bB/2);
- FAv = Fv - FBv;
- FAh = Fh*(0.03/2 + bA/2)/(0.03 + bA/2 + bB/2);
- FBh = Fh - FAh;
- FAr = sqrt(FAv^2 + FAh^2)
- FBr = sqrt(FBv^2 + FBh^2)
- % Gissade värden på spänningskoncentrationsfaktorer
- alfaAv = 2;
- alfaAb = 2;
- alfaBb = 2;
- % Lagerdiameter
- dA = (1/(pi*sigmaTN)^2*((16*alfaAb*FAr*bA)^2 + 3*(alfaAv*16*M)^2))^(1/6)
- dB = (16*alfaBb*FBr*bB/(pi*sigmaTN))^(1/3)
- %% Uppgift 4
- L10h = 20E3;
- CA = ((L10h*60*nmin)/1E6)^(1/3) * FAr
- CB = ((L10h*60*nmin)/1E6)^(1/3) * (0.56*FBr + 1*FBa)
- %% Uppgift 5
- f0 = 13;
- C0 = 2.36E3;
- f = f0*FBa/C0
- % Linjär interpolation
- f1 = 2.07;
- f2 = 3.45;
- Y1 = 1.31;
- Y2 = 1.15;
- Y = Y1 + (f-f1)*(Y2-Y1)/(f2-f1);
- % Nya värden på spänningskoncentrationsfaktorer och bredd ger nya d och C
- bAny = 0.0035;
- bBny = 0.009;
- alfaAvny = 1.8;
- alfaAbny = 2.9;
- alfaBbny = 1.9;
- % Nya krafter pga nya alfa och b
- FBvny = (Fv*(0.03/2 + bAny/2) - Fa*R)/(0.03 + bAny/2 + bBny/2);
- FAvny = Fv - FBvny;
- FAhny = Fh*(0.03/2 + bAny/2)/(0.03 + bAny/2 + bBny/2);
- FBhny = Fh - FAhny;
- FArny = sqrt(FAvny^2 + FAhny^2);
- FBrny = sqrt(FBvny^2 + FBhny^2);
- dAny = (1/(pi*sigmaTN)^2*((16*alfaAbny*FArny*bAnyny)^2 + 3*(alfaAvny*16*M)^2))^(1/6)
- CAny = ((L10h*60*nmin)/1E6)^(1/3) * FArny
- dBny = (16*alfaBbny*FBrny*bBny/(pi*sigmaTN))^(1/3)
- CBny = ((L10h*60*nmin)/1E6)^(1/3) * (0.56*FBrny + Y*FBa)
- % Testa igen med 619/7 och *6200
- % Nya värden på spänningskoncentrationsfaktorer och bredd
- bAnyny = 0.005;
- bBny = 0.009;
- alfaAvnyny = 1.7;
- alfaAbnyny = 2.1;
- alfaBbny = 1.9;
- % Nya krafter pga nya alfa och b
- FBvny = (Fv*(0.03/2 + bAnyny/2) - Fa*R)/(0.03 + bAnyny/2 + bBny/2);
- FAvny = Fv - FBvny;
- FAhny = Fh*(0.03/2 + bAnyny/2)/(0.03 + bAnyny/2 + bBny/2);
- FBhny = Fh - FAhny;
- FArny = sqrt(FAvny^2 + FAhny^2);
- FBrny = sqrt(FBvny^2 + FBhny^2);
- dAverk = 0.007;
- dBverk = 0.010;
- sigmaAjmf = sqrt((alfaAbnyny*32*FArny*bAnyny/2/(pi*dAverk^3))^2 + 3*(alfaAvnyny*16*M/(pi*dAverk^3))^2)
- sigmaBjmf = (alfaBbny*32*FBrny*(bBny/2))/(pi*dBverk^3)
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