#include <stdlib.h>
#include <stdio.h>
#include <string.h>
#define WORDS 10
#define COL 50
#define ASCII_A 97
#define ASCII_Z 122
#define NUM_LETTERS 26
//This code is taking the words that the user entered and checks if the sentence is pangram.
int main(void)
{
	int notYet = 1; // It's showing if it's already a pangram.
	int englet = 0;
	int engLetter = 0;
	int word = 0;
	int letter = 0;
	int i = 0;
	int j = 0;
	char englishLetters[NUM_LETTERS] = {0};
	char pangram[WORDS][COL] = {0};
	printf("Enter up to 10 words, try to make a pangram:\n");
	for(i = 0; (i < WORDS) && (notYet > 0); i++)
	{
		for(j = 0; j < NUM_LETTERS; j++)
		{
			englishLetters[j] = 1;
		}
		fgets(pangram[i], WORDS, stdin);
		if(strlen(pangram[i]) < COL)
		{
			pangram[i][strlen(pangram[i])-1] = 0;
		}
		for(englet = ASCII_A; englet <= ASCII_Z; englet++)
		{
			for(word = 0; word < WORDS; word++)
			{
				for(letter = 0; letter < strlen(pangram[word]); letter++)
				{
					if((pangram[word][letter] == englet) && (englishLetters[engLetter] != 0))
					{
						englishLetters[engLetter] = 0;
					}
				}
			}
		}
		notYet = 0;
		for(englet = 0; (englet > NUM_LETTERS) && (notYet == 0); englet++)
		{
			if(englishLetters[englet] != 0)
			{
				notYet++;
				printf("\n");
			}
		}
		engLetter++;
	}
	if(notYet == 0)
	{
		printf("It's a pangram?\nYes!");
	}
	else
	{
		printf("It's a pangram?\nNo");
	}
	return(0);
}