asdasd

#We will assume the data structure with the valid four letter words is in a list.

import sys              # To take command line arguements.

array = [hello]

inputNum = str(sys.argv[0])


my2DArray = [['a', 'b', 'c'], ['d', 'e', 'f'], ['g', 'h', 'i'], ['j', 'k', 'l'], ['m', 'n', 'o'], ['p', 'q', 'r', 's'], ['t', 'u', 'v'], ['w', 'x', 'y', 'z']]

for i = 0; i < len(array); i++                                  # iterating through the each valid word in array

        for j = 0; j < len(my2DArray[numb]); j++                # iterates each possible thing the dial number could be and the letters in the word
            numb - 2 = inputNum[j]                              # accounting for the number starting at 2
            word = array[i]                                     # narrow the word
            if(word[j] == my2DArray[numb][j])                   # check if the letter in the word is = to one of the
                if(j + 1 == len(my2DArray[numb]))
                    newArray.append(array[i])
                continue
            else if(j + 1 == len(my2DArray[numb]))
                i++
                break