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Mar 19th, 2018
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  1. getPedido(login as string, passwd as string, XML as string) as String
  2.  
  3. string login = "6408";
  4. string senha = "2448";
  5. var xmlEnvio = File.ReadAllText(@"C:TempHX120180228001.XML");
  6. string xml;
  7. string[] dados = null;
  8. XmlDocument xmlText = new XmlDocument();
  9. ws.XMLServer ws = new wsp.XMLServer();
  10.  
  11. xml = ws.getPedido(login, senha,xmlEnvio);
  12.  
  13. Informações adicionais: mensagem SOAP mal formada.
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