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  1. \documentclass[10pt]{article}
  2. \usepackage[a4paper,margin=1.5cm]{geometry}
  3. \usepackage{fouriernc}
  4. \usepackage{xcolor}
  5. \usepackage{amsmath}
  6. \usepackage[shortlabels]{enumitem}
  7. \begin{document}
  8.  
  9. \begin{minipage}[t]{.475\textwidth}
  10. \textbf{Soal.}\\
  11. Bentuk sedrhana dari $\displaystyle\frac{\left(\sqrt{3}+\sqrt{7}\right)\left(\sqrt{3}-\sqrt{7}\right)}{2\sqrt{5}-4\sqrt{2}}$ adalah \ldots.
  12. \begin{enumerate}[A.,leftmargin=*]
  13.    \item $\displaystyle\tfrac{2}{3}\left(\sqrt{5}+2\sqrt{2}\right)$
  14.    \item $\displaystyle\tfrac{2}{3}\left(2\sqrt{2}-\sqrt{5}\right)$
  15.    \item $\displaystyle-\tfrac{2}{3}\left(2\sqrt{5}+4\sqrt{2}\right)$
  16.    \item $\displaystyle-\tfrac{4}{9}\left(2\sqrt{5}+4\sqrt{2}\right)$
  17.    \item $\displaystyle-\tfrac{4}{9}\left(2\sqrt{5}-\sqrt{2}\right)$
  18. \end{enumerate}
  19. \end{minipage}\hfill
  20. {\color{orange}\vrule}\hfill%
  21. \begin{minipage}[t]{.475\textwidth}
  22. \textbf{Jawaban: A}
  23. \begin{align*}
  24. \frac{\left(\sqrt{3}+\sqrt{7}\right)\left(\sqrt{3}-\sqrt{7}\right)}{2\sqrt{5}-4\sqrt{2}} &=
  25. \frac{3-7}{2\left(\sqrt{5}-2\sqrt{2}\right)} \\
  26. &= \frac{-4}{2\left(\sqrt{5}-2\sqrt{2}\right)}\\
  27. &= \frac{-2}{\sqrt{5}-2\sqrt{2}}{\color{red}{}\times\frac{\sqrt{5}+2\sqrt{2}}{\sqrt{5}+2\sqrt{2}}}\\
  28. &= \frac{-2\left(\sqrt{5}+2\sqrt{2}\right)}{5-8}\\
  29. &= \tfrac{2}{3}\left(\sqrt{5}+2\sqrt{2}\right)
  30. \end{align*}
  31. \end{minipage}
  32.  
  33. \end{document}