function solution(S) {
 let total = 0;

 const callArr = S.split('\n');
 let callMap = {};

 for (let i=0; i<=callArr.length-1; i++) {
 const tempArr = callArr[i].split(',')
 if (!callMap[tempArr[1]]) callMap[tempArr[1]] = { 'cost' : 0, 'duration' : 0 }
 callMap[tempArr[1]].cost = callCost(tempArr[0].split(':'))
 callMap[tempArr[1]].duration += secondsCalled(tempArr[0].split(':')) //duration is in seconds
 }

 callMap = longestCall(callMap);
 for (let num in callMap) {
 total += callMap[num].cost;
 }

 return total;
}
function callCost(duration) {
 let m = (Number(duration[0])*60) + Number(duration[1]);
 let s = Number(duration[2]);

 if (m >= 5) {
 if (s > 0) m++;
 return m*150;
 } else {
 s += m*60
 return s*3
 }
}
function secondsCalled(duration) {
 return (Number(duration[0])*60) + Number(duration[1])*60 + Number(duration[2])
}
function longestCall(callMap) {
 let mostCalled = '';
 let mostSeconds = 0;
 for (let num in callMap) {
 if (callMap[num].duration === mostSeconds) {
 const currNumArr = num.split('-');
 const currVal = Number(currNumArr[0]+currNumArr[1]+currNumArr[2]);

 const mostArr = num.split('-');
 const mostVal = Number(mostArr[0]+mostArr[1]+mostArr[2]);

 // What if the numerical values of the phone numbers are equal? No details in spec for that case...
 if (currVal < mostVal) mostCalled = num;
 }
 if (callMap[num].duration > mostSeconds) {
 mostSeconds = callMap[num].duration;
 mostCalled = num;
 }
 }

 delete callMap[mostCalled];
 return callMap;
}